2/3x^2-10/3x=-6

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Solution for 2/3x^2-10/3x=-6 equation: 


x in (-oo:+oo)

(2/3)*x^2-((10/3)*x) = -6 // + 6

(2/3)*x^2-((10/3)*x)+6 = 0

(2/3)*x^2+(-10/3)*x+6 = 0

2/3*x^2-10/3*x+6 = 0

DELTA = (-10/3)^2-(2/3*4*6)

DELTA = -44/9

DELTA < 0

x belongs to the empty set

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